Question

Print reverse of a number in given range using recursion

				
					ENTER THE LOWER RANGE
25
ENTER THE UPPER RANGE
35
Reverse of 25 is 52
Reverse of 26 is 62
Reverse of 27 is 72
Reverse of 28 is 82
Reverse of 29 is 92
Reverse of 30 is 3
Reverse of 31 is 13
Reverse of 32 is 23
Reverse of 33 is 33
Reverse of 34 is 43
Reverse of 35 is 53

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Code

				
					import java.util.Scanner;
public class Reverse
{
    public static long findReverse(long num,long rev)
    {
        if(num==0)
        {
            return rev; 
        }
        else
        {
            rev=rev*10+num%10;
            return findReverse(num/10,rev);   
        }
    }

    public static void main()
    {

        long lowerRange=0,upperRange=0,reverse=0,i=0;
        Scanner sc=new Scanner(System.in);
        System.out.println("ENTER THE LOWER RANGE");
        lowerRange=sc.nextLong();
        System.out.println("ENTER THE UPPER RANGE");
        upperRange=sc.nextLong();
        for(i=lowerRange;i<=upperRange;i++)
        {
            reverse=findReverse(i,0);
            System.out.println("Reverse of "+i+" is "+reverse);
        }

    }
}