Question

Find the factorial of a number in a given range using recursion

				
					ENTER THE LOWER NUMBER:1
ENTER THE UPPER NUMBER:25
Factorial of numbers
1:1
2:2
3:6
4:24
5:120
6:720
7:5040
8:40320
9:362880
10:3628800
11:39916800
12:479001600
13:6227020800
14:87178291200
15:1307674368000
16:20922789888000
17:355687428096000
18:6402373705728000
19:121645100408832000
20:2432902008176640000
21:51090942171709440000
22:1124000727777607680000
23:25852016738884976640000
24:620448401733239439360000
25:15511210043330985984000000

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Code

				
					import java.util.Scanner;
import java.math.BigInteger;
class FactorialOfNumber
{
    public static BigInteger Factorial(long num)
    {

        if(num==1)
        {
            return BigInteger.valueOf(1);
        }
        else
        {
            return Factorial(num-1).multiply(BigInteger.valueOf(num));
        }
    }

    public static void main(String args[])
    {
        long lowerRange=0,upperRange=0,i=0;
        BigInteger fac=new BigInteger("1");
        Scanner sc=new Scanner(System.in);
        System.out.print("ENTER THE LOWER NUMBER:");
        lowerRange=sc.nextLong();
        System.out.print("ENTER THE UPPER NUMBER:");
        upperRange=sc.nextLong();
        System.out.println("Factorial of numbers");
        for(i=lowerRange;i<=upperRange;i++)
        {
            if(i>0)
            {
                fac=Factorial(i);
                System.out.println(i+":"+fac);

            }

        }

    }
}