Question

Print Armstrong number in a given range using recursion.

A positive number is called Armstrong number if the sum of its own digits each raised to the power of the number of digits is equal to the number.

				
					ENTER THE LOWER RANGE
1
ENTER THE UPPER RANGE
50
ARMSTRONG NUMBERS BETWEEN 1 AND 50
1 2 3 4 5 6 7 8 9

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Code

Java

Python

Java

				
					import java.util.Scanner;
public class ArmstrongNumber
{
    public static int SumOfDigit(int num,int i)
    {
        if(num==0)
        {
            return 0;
        }
        else
        {
            return (int)Math.pow(num%10,i)+SumOfDigit(num/10,i);
        }
    }

    public static void main()
    {
        int sum=0,noOfDigits=0,lowerRange=0,upperRange=0,i=0;
        Scanner sc=new Scanner(System.in);
        System.out.println("ENTER THE LOWER RANGE");
        lowerRange=sc.nextInt();
        System.out.println("ENTER THE UPPER RANGE");
        upperRange=sc.nextInt();
        System.out.println("ARMSTRONG NUMBERS BETWEEN "+lowerRange+" AND "+upperRange);
        for(i=lowerRange;i<=upperRange;i++)
        {
            noOfDigits=Integer.toString(i).length();
            sum=SumOfDigit(i,noOfDigits);
            if(sum==i)
            {
                System.out.print(i+" ");

            }
        }

    }
}

Python

				
					def sumOfDigits(num):
    if(num<=0):
        return 0
    else:
        digit=num%10
        return digit**totalDigits+sumOfDigits(num//10)

#Main Method Starts from here
if(__name__=='__main__'):
    lowerRange=int(input("Enter the lower Value:"))
    upperRange=int(input("Enter the upper Value:"))
    print("Armstrong number between",lowerRange,"and",upperRange,":")
    for number in range(lowerRange,upperRange+1):
        totalDigits = len(str(number))
        """
            str(number) converted integer to string
            len() gives length of string
            so len(str(number)) combined gives total number of digits
        """
        sum = sumOfDigits(number)
        if (sum == number):
            print(number,end=" ")