Question

Check whether a number is a Prime Palindrome number using recursion.

A prime palindrome integer is a positive integer (without leading zeroes) which is prime as well as a palindrome.

ENTER THE NUMBER
101
101 IS A PRIME PALINDROME NUMBER

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Code

import java.util.Scanner;
public class PrimePalindromeNumber
{
    long num=0;
    public void accept()
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("ENTER THE NUMBER");
        num=sc.nextLong();
    }

    public long FindReverse(long num,long reverse)
    {
        if(num==0)
        {
            return reverse;
        }
        else
        {
            reverse=reverse*10+num%10;
            return FindReverse(num/10,reverse);
        }
    }

    public  boolean checkPrime(long n,long i)
    {
        if(n< 2)
        {
            return false;
        }
        /*Check if i is greater than n/2 because if any number is divisible by another number till another number is less than or equal to num/2*/
        else if(i>(n/2))
        {
            return true;
        }

        else if(n%i==0)
        {
            return false;
        }
        else
        {
            return  checkPrime(n,(i+1));
        }
    }

    public void display()
    {

        if(checkPrime(num,2)==true && num==FindReverse(num,0))
        {
            System.out.println(num+" IS A PRIME PALINDROME NUMBER");
        }
        else
        {
            System.out.println(num+" IS NOT A PRIME PALINDROME NUMBER");
        }

    }

    public static void main(String args[])
    {
        PrimePalindromeNumber ob1=new PrimePalindromeNumber();
        ob1.accept();
        ob1.display();
    }

}