Question

Check whether a number is Palindrome number using recursion

(A palindrome number is a number that remains the same when its digits are reversed)

ENTER THE NUMBER
121
121 IS A PALINDROME NUMBER

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Code

Java

Python

Java

import java.util.Scanner;
public class PalindromeNumber
{

    public static long FindReverse(long num,long rev)
    {
        if(num<=0)
        {
            return rev;
        }
        else
        {
            rev=rev*10+num%10;
            return FindReverse(num/10,rev);
        }
    }

    public static void main()
    {

        long num=0,reverse=0;
        Scanner sc=new Scanner(System.in);
        System.out.println("ENTER THE NUMBER");
        num=sc.nextLong();

        reverse=FindReverse(num,0);
        if(num==reverse)
        {
            System.out.println(num+" IS A PALINDROME NUMBER");

        }
        else
        {
            System.out.println(num+" IS NOT A PALINDROME NUMBER");

        }
    }

}

Python

def reverseOfNumber(num,rev=0):
    if(num<=0):
        return rev
    else:
        digit=num%10
        rev=rev*10+digit
        return reverseOfNumber(num//10,rev)
number=int(input("Enter a number:"))
reversedNumber=reverseOfNumber(number)
if(number==reverseOfNumber):
    print(number,"is a Palindrome number")
else:
    print(number, "is not a Palindrome number")