Question

Program to determine whether a given number is a Disarium number in a given range.

(A number is said to be the Disarium number when the sum of its digit raised to the power of their respective positions is equal to the number itself.)

				
					Enter the lower range
1
Enter the Upper range
500
Disarium  Numbers:1    2    3    4    5    6    7    8    9    89    135    175

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Code

Java

Python

Java

				
					import java.util.Scanner;
public class disariumNumberInRange
{
    public static void main(String[] args)
    {
        int  sum = 0, rem = 0, temp=0,i=0,upperRange=0,lowerRange=0,len=0;
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the lower range");
        lowerRange=sc.nextInt();
        System.out.println("Enter the Upper range");
        upperRange=sc.nextInt();
        System.out.print("Disarium  Numbers:");
        for(i=lowerRange;i<=upperRange;i++)
        {
            temp=i;
            while(temp>0)
            {
                len=len+1;
                temp=temp/10;
            }
            sum=0;
            /*Makes a copy of the original number num*/
            temp = i;

            /*Calculates the sum of digits powered with their respective position */
            while(temp > 0)
            {
                rem = temp%10;
                sum = sum + (int)Math.pow(rem,len);
                temp = temp/10;
                len--;
            }

        /*Checks whether the sum is equal to the number itself  */
            if(sum == i)
            {
                System.out.print(i + "    ");
            }
        }
    }
}

Python

				
					lowerRange = int(input("Enter lower value:"))
upperRange = int(input("Enter upper value:"))
print("Disarium number between ", lowerRange, "and", upperRange, ":")
# counting total number of digits in the given number
for i in range(lowerRange, upperRange + 1):
    temp = i
    totalDigits = 0
    while (temp > 0):
        totalDigits = totalDigits + 1
        temp = temp // 10
    # calculating sum
    temp = i
    sumOfDigits = 0
    while (temp > 0):
        rem = temp % 10
        sumOfDigits = sumOfDigits + rem ** totalDigits
        totalDigits = totalDigits - 1
        temp = temp // 10

    if (sumOfDigits == i):
        print(i, end=" ")