Question
program to Largest element in boundary elements of matrix
Matrix = [9, 8, 7]
[6, 5, 4]
[3, 2, 1]
SMALLEST BOUNDARY ELEMENT IN MATRIX:1
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Code
Java
Python
Java
import java.util.Scanner;
public class SmallestBoundaryElementsOfMatrix
{
public static void main(String[] args)
{
int row=0,col=0,i=0,j=0,min=0;
int a[][];
Scanner sc=new Scanner(System.in);
System.out.println("ENTER THE NUMBER OF ROW OF MATRIX");
row=sc.nextInt();
System.out.println("ENTER THE NUMBER OF COLUMN OF MATRIX");
col=sc.nextInt();
a=new int[row][col];
System.out.println("ENTER THE ELEMENTS IN MATRIX");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
a[i][j]=sc.nextInt();
}
}
System.out.println("MATRIX:");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
System.out.print(a[i][j]+" ");
}
System.out.println();
}
min=a[0][0];
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
if(i==0 ||j==0||i==(row-1)||j==(col-1))
{
if(a[i][j]< min)
{
min=a[i][j];
}
}
}
}
System.out.println("SMALLEST BOUNDARY ELEMENT IN MATRIX:"+min);
}
}
Python
import numpy as np
row=int(input("Enter number of rows:"))
columns=int(input("Enter number of columns:"))
matrix=np.empty([row,columns],dtype=np.int)
# Taking input from user
print("Enter elements in matrix:")
for i in range(0,row):
for j in range(0,columns):
print("(",(i+1),",",(j+1),")",":",end="")
matrix[i,j]=int(input())
#printing the matrix
print("Matrix:")
for i in range(0, row):
print(matrix[i])
smallestBoundaryElement=matrix[0,0]
#Finding smallest boundary elements
for i in range(0,row):
for j in range(0,columns):
if(i==0 or j==0 or i==(row-1) or j==(columns-1)):
if(matrix[i,j]< smallestBoundaryElement):
smallestBoundaryElement=matrix[i,j]
print("smallest boundary elements:",smallestBoundaryElement)