Question
Write a program to declare a matrix a[][] of order (m × n) where ‘m’ is the number of rows and ‘n’ is the number of columns such that the values of both ‘m’ and ‘n’ must be greater than 2 and less than 10. Allow the user to input integers into this matrix. Perform the following tasks on the matrix:
Display the original matrix.
Sort each row of the matrix in ascending order using any standard sorting technique.
Display the changed matrix after sorting each row.
Test your program for the following data and some random data:
Example 1:
INPUT:
m = 4
n = 3
Enter elements of matrix:
11 -2 3
5 16 7
9 0 4
3 1 8
OUTPUT:
ORIGINAL MATRIX:
11 -2 3
5 16 7
9 0 4
3 1 8
MATRIX AFTER SORTING:
-2 3 11
5 7 16
0 4 9
1 3 8
Example 2:
INPUT:
m = 3
n = 3
Enter elements of matrix:
22 5 19
7 36 12
9 13 6
OUTPUT:
ORIGINAL MATRIX:
22 5 19
7 36 12
9 13 6
MATRIX AFTER SORTING:
5 19 22
7 12 36
6 9 13
INPUT:
m = 11
n = 5
OUTPUT:
Matrix size out of range.
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Code
import java.util.Scanner;
public class SortMatrix
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int m = 0,n=0,i=0,j=0,k=0,temp=0;
int a[][];
System.out.print("M = ");
m = sc.nextInt();
System.out.print("N = ");
n = sc.nextInt();
if(m <= 2 || m >= 10 || n <= 2 || n >= 10)
{
System.out.println("Matrix size out of range.");
return;
}
a = new int[m][n];
System.out.println("Enter elements of matrix:");
for(i = 0; i < m; i++)
{
for(j = 0; j < n; j++)
{
a[i][j] = sc.nextInt();
}
}
System.out.println("Original Matrix:");
for(i = 0; i < m; i++)
{
for(j = 0; j < n; j++)
{
System.out.print(a[i][j] + "\t");
}
System.out.println();
}
/*sorting array by row */
for(i = 0; i < m; i++)
{
for(j = 0; j < n; j++)
{
for(k=0;k< n;k++)
{
if(a[i][j] < a[i][k])
{
temp=a[i][j];
a[i][j] =a[i][k];
a[i][k]=temp;
}
}
}
}
System.out.println("Matrix after sorting rows:");
for(i = 0; i < m; i++)
{
for(j = 0; j < n; j++)
{
System.out.print(a[i][j] + "\t");
}
System.out.println();
}
}
}